(5+4i)(17-13i)-(5+3i)(17-13i)

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asked Aug 1, 2015 152 views

1 Answer

Konstantin Cherkasov · Answer 1 · 2015-08-08T10:01:07+0000

use distributive property and multiply first
(85-65i+68i-52i^2)-(85-65i+51i-39i^2)
(85+3i-52i^2)-(85-14i-39i^2) the subtraction sign applies to each part so
85+3i-52i^2-85+14i+39i^2 then add like terms
17i-13i^2

i^2 means i squared.

(5+4i)(17-13i)-(5+3i)(17-13i)

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