Question

In the nth term of a sequence is n2+50
what are the first 3 terms

Answer 1

Would assume this to be: n² + 50

First term, n=1, n² + 50 = 1² + 50 = 1*1 + 50 = 1 + 50 = 51

Second term, n=2, n² + 50 = 2² + 50 = 2*2 + 50 = 4 + 50 = 54

Third term, n=3, n² + 50 = 3² + 50 = 3*3 + 50 = 9 + 50 = 59

First three terms are: 51, 54, & 59.