Question

A piece of art is in the shape of an equilateral triangle with sides of 6 in. Find the area of the piece of art. Round your answer to the nearest tenth

A. 12.7 in2
B. 15.6 in2
C. 31.2 in2
D. None of these

Answer 1

Area of equilateral triangle = s²√3/4

Where s = length of side

s = 6

Area, A = s²√3/4 = 6²√3/4 = 36*√3/4 = 9√3

A = 9√3 = 9 * 1.732 ≈ 15.588

A ≈ 15.6 in² to the nearest tenth. (B)

Answer 2

(B)
`15.6 in^2`

Explanation:

Given: A piece of art is in the shape of an equilateral triangle with sides of 6 in.

To find: The area of the piece of art.

Solution: Since, the piece of art is in the shape of an equilateral triangle, thus the area of equilateral triangle=
`(√(3))/(4){*}(side)^(2)`

=
`(√(3))/(4){*}(6)^2`

=
`(√(3))/(4){*}6{*}6`

=
`9√(3)`

=
`9(1.732)`

=
`15.6 in^2`

Therefore, area of the piece of art=
`15.6 in^2`