Question

A spring has a spring constant of 200 N/m. How much elastic potential energy is stored in the spring when it is stretched by 0.1 meters? A:2000 J B:20 J C:0 J D:1 J

Answer 1

D, 1J

Step-by-step explanation:

PE=1/2kx^2 and plug in the variables.

PE=1/2 x 200 x 0.1^2= 1J