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What is base 1 of a trapezoid in which A=(48x+68) in^2, height =8, and base 2 = (9x + 12)

What is base 1 of a trapezoid in which A=(48x+68) in^2, height =8, and base 2 = (9x + 12)
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What is base 1 of a trapezoid in which A=(48x+68) in^2, height =8, and base 2 = (9x + 12)

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User Hongsy
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8.5k points

1 Answer

1 vote
A=(1/2)(b1+b2)h =

=(48x+68)in² = (1/2)( b1+(9x+12))8

the answer is = b1= 3x+5

i hope that helped =D
answered
User Smichr
by
7.7k points
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