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When will the equation xn = c, where c is a whole number, have two solutions? Explain.

I am so confused!! Help please!!!

asked
User Sesame
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8.2k points

2 Answers

1 vote
I think the answer but I'm not totally sure based on what you are asking but I think that the two solutions would be 1 and 0. This is because any number multiplied by 1 would get that number itself and 0 because a number and zero would just get you zero. Hope it helped. 
answered
User Hisham Hijjawi
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8.3k points
5 votes
I'm very uncomfortable here. It's as if there's
some more information lurking just out of sight.

Normally, a "solution" means a value for 'x' that makes
the equation a true statement.

If that's true, and 'c' has to be a whole number, then any
rational value of 'n' gives an infinite number of possible
values for 'x'.

Examples:

-- If n = 7/3 , then 'c' is a whole number when 'x' is any multiple of 3.
There are an infinite number of those.

-- If n = 1, then 'c' is a whole number when 'x' is any whole number.
There are an infinite number of those.

-- If n = 0, then c=0 whenever 'x' is anything at all.
There are an infinite number of those.

-- Ah hah ! Maybe I found something.
If 'n' is an irrational number, then
-- c = 1 when x = 1/n , and
-- c = -1 when x= -1/n ,
and those are the only two whole numbers that 'c' can be.

So I have two conclusions:
#1). I have solved the problem exactly as you stated it.
#2). I can't believe that this is the way it was assigned,
or that this was the intended answer.
There's something missing.

answered
User ShashaDenovo
by
8.6k points

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