Question

B^2-4b+4=0
Quadratic formula

Answer 1

`b^2-4b+4=0 \\ \\ b = (-(-4) \pm √((-4)^2 - 4(1)(4)) )/(2(1)) \\ \\ b = (-(-4))/(2(1)) \\ \\ b = 2 \\ \\`

The final result is: b = 2.