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4 votes
What is square root of 126 + square root of 56 in standard form

2 Answers

7 votes

√(126)+√(56)=√(9*14)+√(4*14)=\sqrt9*√(14)+\sqrt4*√(14)\\\\=3√(14)+2√(14)=5√(14)
6 votes

√(126)= 3√(14) \\ \\ √(56)=2√(14) \\ \\ \\ √(126)+ √(56)= 3√(14)+2√(14)= 5√(14)
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User Shane Perry
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