Question

This is a literal equation.

Solve for A.

2 2
V = V_0 + 2aΔx




( The second 'V' variable is squared and subscripted with a zero)

Answer 1

`V^2=V_0^2+2a\Delta x\\ 2a\Delta x=V^2-V_0^2\\ a=(V^2-V_0^2)/(2\Delta x)`

Answer 2

Assuming this is the equation you want to operate on:

`v^(2) = (v_0)^(2) + 2\cdot a \cdot \Deltax`

`2\cdot a \cdot \Delta x = v^(2) - (v_0)^(2)`

`a = (v^(2) - (v_0)^(2))/(2\cdot \Delta x)`
Before final operation we have to assume that x is not equal to 0. :)