Question

Solve each system using substitution:
2x+2y=38
y=x+3

Answer 1

2x+2(x+3)=38
2x+2x+6=38
4x+6=38
4x=32
x=8

y=8+3
y=11

Answer 2

`2x+2y=38 \\ y = x + 3 \\ \\ \\ 2x+ 2 (x + 3) = 38 \\ \\ 2x + 2(x + 3) \\ \\ 2x + 2x + 6 \\ \\ 4x + 6 \\ \\ 4x + 6 = 38 \\ \\ 4x + 6 - 6 = 38 - 6 \\ \\ 4x = 32 \\ \\ (4x)/(4) = (32)/(4) \\ \\ x = 8 \\ \\ y = 11 \\ \\`

The final result is: x = 8 and y = 11.