Question

Twice the product of 3and a number exceeds the sum of the number and 80 by 10.what is the number?

Answer 1

First, create an equation with the criteria given.

If we let x be your number,

`2(3x) = 80 + x + 10`
(
`2(3x)` is twice the product of 3 and x, and if it exceeds
`x+80` by 10, then we add 10 to
`x+80` to make the two sides of the equation equal.)

Now, solve for
`x`.


`6x=90+x \\ 5x=90 \\ x=18`