Question

A bowl contains candies of the same size in three flavors: orange, strawberry, and pineapple. If the probability of randomly pulling out an orange candy is fraction 2 over 8, and the probability of randomly pulling out a strawberry candy is fraction 3 over 8, what is the probability of randomly pulling out a pineapple candy?

Answer 1

There is an equal likely to pull out a strawberry candy and a pineapple candy because there is a 3 over 8 likely to pull out a pineapple candy.

Answer 2

The probability of randomly pulling out a pineapple candy is fraction 3 over 8.

Explanation:

A bowl contains only three flavors of candies: orange, strawberry and pineapple. Then, the sum of probabilities of pulling out any flavor of the candies need to be one, this can be write as:

`(2)/(8) +(3)/(8) + X = 1`

Where the fraction 2 over 8 is the probability of randomly pulling out an orange candy, the fraction 3 over 8 is the probability of randomly pulling out a strawberry candy and X is the probability of randomly pulling out a pineapple candy.

Solving for X, we get:

`X=1-(2)/(8) -(3)/(8)`

`X=(3)/(8)`

Finally, the probability of randomly pulling out a pineapple candy is fraction 3 over 8.