asked 135k views
5 votes
Solve using quadratic formula

2k {}^(2) - 3 = 0


asked
User Skalee
by
7.7k points

1 Answer

7 votes

Answer:


\bold{k=\pm(\sqrt6)/(2)\approx\pm1.22}

Explanation:


2k^2-3=0\\\\a=2\,,\ \ b=0\,,\ \ c=-3\\\\k=(-0\pm√(0^2-4\cdot2\cdot(-3)))/(2\cdot2)=(\pm√(24))/(2\cdot2)=(\pm2√(6))/(2\cdot2)=\pm(\sqrt6)/(2)\approx\pm1.22

answered
User HigherDefender
by
8.7k points

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