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How do you use implicit differentiation to find x^2+3xy+y^3=10

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User Sacse
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1 vote

Answer:


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answered
User KuldipKoradia
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x^2+3xy+y^3=10\\2x+3xy'+3y+2yy'=0\\(2x+3y)+(3xy'+2yy')=0\\2x+3y+(3x+2y)y'=0\\(3x+2y)y'=-2x-3y\ /\ :\ (3x+2y)\\y'=(-2x-3y)/(3x+2y)


answered
User Pranav Naxane
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