Question

A car travels at a constant speed around a circular track whose radius is 2.9 km. the car goes once around the track in 400 s. what is the magnitude of the centripetal acceleration of the car?

Answer 1

First we need the linear velocity
D=2*Pi*r=2*pi* 2.9=18.22 km=18,221.23m
V=D/T=18,221.23m/400s= 45.55 m/s
A=V^2/r=(45.55 m/s)^2/2900m= 0.72 m/s^2
the magnitude of the centripetal acceleration of the car is 0.72 m/s^2