Question

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water

When 3.00 moles of hydrogen molecules and 1.50 moles of oxygen molecules react, they form 3.00 moles of water
according to the reaction below.
2H2+ O2 + 2H2O
How many grams of oxygen were required?

2H, + O2 + 2H2O
How many grams of oxygen were required?

Answer 1

Mass of Oxygen required : 24 grams

Further explanation

Given

3 moles of H

1.5 moles of O

3 moles of H₂O

Required

Mass of O

Solution

Reaction

2H₂ + O₂ ⇒ 2H₂O

Mass of Oxygen for 1.5 moles of O :

= mol x Ar O

= 1.5 moles x 16 g/mol

= 24 grams