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The equilibrium constant, k c, for the reaction n2o4 (g) ⇄ 2no2 (g) is 0.211 at 100°c. if the equilibrium concentration of n2o4 is 0.00251 m, calculate the equilibrium concentration of no2.

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Final answer:

To calculate the equilibrium concentration of NO2 in the reaction N2O4(g) ⇄ 2NO2(g), we can use the given equilibrium constant and concentration of N2O4. The equilibrium concentration of NO2 is approximately 0.0175 M.

Step-by-step explanation:

To calculate the equilibrium concentration of NO2, we can use the equilibrium constant expression and the given equilibrium concentration of N2O4. The equilibrium constant expression for the reaction N2O4(g) ⇄ 2NO2(g) is Kc = [NO2]^2 / [N2O4].

Given that Kc = 0.211 and [N2O4] = 0.00251 M, we can set up the following equation:

0.211 = [NO2]^2 / 0.00251

[NO2]^2 = 0.211 * 0.00251

[NO2] = √(0.211 * 0.00251)

[NO2] ≈ 0.0175 M

answered
User Semyon Burov
by
8.5k points
6 votes
Answer is: 0.0213M.
Reaction: N₂O₄ (g) ↔ 2NO₂ (g).
Kc = 0,211 at 100°C.
Kc - equilibrium constant.
c (N₂O₄) = [N₂O₄] = 0,00251M.
c (NO₂) = [NO₂] = ?
Kc = [NO₂]² / [N₂O₄]
[NO₂]² = Kc · [N₂O₄]
[NO₂] = √(Kc · [N₂O₄])
[NO₂] = √(0.211 · 0.00215M)
[NO₂] = 0.0213M.
answered
User Denim Demon
by
8.5k points
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