Question

) find a pair of numbers (2), whose sum is 16, and product is 48.

Answer 1

a+b=16 ____[1]
a*b=48 ____[2]

[1] a=16-b ___[3]
put [3] in [2] (16-b)*b = 48
16b-b^2 = 48
b^2-16b+48=0
(b-12)(b-4) = 0
b= 12 or b=4
so if b= 12, a=16-12=4
if b=4, a=16-4=12

then a pair of numbers is 4 and 12