Question

Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary. B = 71°, a = 11 cm, c = 18 cm

Answer 1

`\boxed{\text{Area of the triangle:} (a * c * sin(\measuredangle B))/(2)} \\ \\ A = (a * c * sin(\measuredangle B))/(2) \\ \\ A= (11 * 18 * sin71 ^o )/(2) \\ \\ \\ Note : sin 71^o \approx 0,94 \\ \\ \\ A = (198 * 0,94)/(2) \\ \\ A= (186.12)/(2) \\ \\ A=93.6 \ cm^2`

Answer 2

93.606 cm^2

Explanation:

Given that in a triangle two sides are 11 and 18 cm and included angle is 71 degrees

`a=11\\c=18\\angleB =71`

We know that area of a triangle when two sides and included angle is known is given by

Area of a triangle =
`(1)/(2) ac sin B\\=(1)/(2) (11)(18)sin 71\\= 99 (0.9455)\\\\=-93.603` cm^2