Question

A radio station has movie tickets to give away: 4 for a new action movie, 5 for a comedy movie, and 3 for a sci-fi movie. The disc jockey reaches into a box to randomly pick tickets as people call in. What is the probability that the first caller will receive a ticket to the comedy and the second will receive a ticket to the action movie?

(a) 0.083

(b) 0.114

(c) 0.139

(d) 0.152

Answer 1

the answer should be a

Answer 2

The answer is the option D

`P=0.152`

Explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

so

Let

x--------> size of the event space

y-------> size of the sample space

The probability

`P=(x)/(y)`

Part 1) Find the probability that the first caller will receive a ticket to the comedy

in this part we have

`x=5\ ticket`

`y=12\ ticket`

`P1=(5)/(12)`

Part 2) Find the probability that the second caller will receive a ticket to the action movie

in this part we have

`x=4\ ticket`

`y=11\ ticket`

`P2=(4)/(11)`

Part 3) Find the probability that the first caller will receive a ticket to the comedy and the second will receive a ticket to the action movie

Multiply P1 and P2

so

`P=(5)/(12)*(4)/(11)=0.152`