Question

Solve for x in the equation x^2+2x+1=17

Answer 1

first, subtract 17 on both sides: x²+2x-16=0
this cannot be factored, so use the quadratic formula to solve for x:
b²-4ac=2²-4(10(-16)=4+64=68
√68=2√17
so x=(-2+2√17)/2 or x=(-2-2√17)/2
x=-1+√17 or x=-1-√17

Answer 2

`x=-1+√(17)` and
`x=-1-√(17)`

Explanation:

`x^2+2x+1=17`

To solve for x , we set the right hand side =0

`x^2+2x+1=17`

Subtract 17 on both sides

`x^2+2x-16=0`

Now apply quadratic formula

`x=(-b+-√(b^2-4ac))/(2a)`

From the given f(x), the value of a=1, b=2, c=-16

Plug in all the values in the formula

`x=(-2+-√(2^2-4(1)(-16)))/(2(1))`

`x=(-2+-√(68))/(2)`

`x=(-2+-2√(17))/(2)`

`x=-1+-√(17)`

`x=-1+√(17)` and
`x=-1-√(17)`