Question

An acute angle θ is in a right triangle with cos θ = 9/10 . What is the value of sec θ?

Answer 1

sec θ=1/cos θ
cos θ=9/10, so sec θ=10/9

Answer 2

The value of sec θ is
`(10)/(9)`

Explanation:

Given,

`cos \theta = (9)/(10)`

Since,

`cos \theta = (1)/(sec \theta)`

`\implies (1)/(sec \theta)=(9)/(10)`

By cross multiplication,

`10=9 sec \theta`

`\implies sec \theta = (10)/(9)`