Question

Write an equation for the line that is parallel to the given line and that passes through the given point. y = –6x + 2; (–1, 2) y = –8x – 8 y = –6x – 4 y = 6x – 8 y = –6x + 4

Answer 1

Parallel=same slope
Y=mx+b
Sub in the slope and point to solve for b
2=-6(-1)+b
2=6+b
2-6=b
-4=b
The equation is y=-6x-4; the answer is B
Hope this helps!

Answer 2

The correct option is B. y = -6x - 4

Explanation:

The given equation of the line : y = -6x + 2

Now, the general equation of the line in the slope-intercept form is given by : y = mx + c

Now, comparing the given equation with the general form, We get slope, m = -6

We need to find the equation of the line which is parallel to the given line and since the slope of two parallel lines are equal so the slope of the required line will also be -6

And it passes through the point (-1, 2)

The required equation will be :

`(y-y_1)=m(x-x_1)`

⇒ y - 2 = -6 × (x + 1)

⇒ y - 2 = -6x - 6

⇒ y = -6x - 4

Therefore, The required equation is y = -6x -4

Hence, The correct option is B. y = -6x - 4