Simplify cube root of 7 / Fifth root of 7 A. 7 to the power of 1 over 5 B. 7 to the power of 8 over 15 C. 7 to the power of 5 over 3 D. 7 to the power of 2 over 15

Question

asked Dec 12, 2018 169k views

2 Answers

MokiSRB · Answer 1 · 2018-12-15T23:28:28+0000

Answer:

Option D. is the answer.

Explanation:

we have to simplify the cube root of
$\frac{\sqrt[3]{7}}{\sqrt[5]{7} }$

=
$\frac{7^{(1)/(3)}}{7^{(1)/(5) } }$

=
$7^{(1)/(3)-(1)/(5)}$

=
$7^{((5-3)/(15))}$

=
$7^{(2)/(15)}$

Therefore, Option D. 7 to the power of 2 over 15 is the answer.