Question

name the theorem or postulate that lets you conclude triangle ABD is congruent to triangle CBD with only one additional step

Answer 1

AAS

Explanation:

***AAS

SAS

ASA

none of the above

Answer 2

The answer is the first one ⇒ AAS

Explanation:

∵ DB ⊥ AC

∴ m∠DBA = m∠DBC = 90° ⇒ (1)

∵ m∠A = m∠C ⇒ (2) given (from figure)

∵ DB is a common side in the two Δ ⇒ (3)

From (1) , (2) and (3)

∴ Δ ABD is congruent to Δ CBD ⇒ AAS