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(2/n-2)-(n-1/n^2-2n)=(n-3/n^2) solve for n please

1 Answer

4 votes
So all said and done, the answer is 1. The process isn't 'hard' but it does take up some space.

1. Find the LCD
2. Multiply all terms by the LCD
3. Cancel out denominators
4. "Clean it up" by collecting like terms and using the distributive property.
5. Solve for n
(2/n-2)-(n-1/n^2-2n)=(n-3/n^2) solve for n please-example-1
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User Vina
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