Question

In the diagram, DG = 12, GF = 4, EH = 9, and HF = 3

To prove that △DFE ~ △GFH by the SAS similarity theorem, it can be stated that and

A. ∠DFE is 4 times greater than ∠GFH.

B. ∠FHG is the measure of ∠FED.

C. ∠DFE is congruent to ∠GFH.

D. ∠FHG is congruent to ∠EFD.

Answer 1

The answer would be: C. ∠DFE is congruent to ∠GFH.

Explanation:

Answer 2

The answer would be: C. ∠DFE is congruent to ∠GFH.

From the question, it is stated that the ratio of DF/GF and EF/HF would be 1:3. The ratio of two sides is already same so you can fulfil the two side criteria from SAS. The remaining is only the angle that should be between those two sides. The angle of DFE should be same with GFH