Question

The ph of a 0.15 m aqueous solution of naz (the sodium salt of hz) is 10.7. what is the ka for hz?

Answer 1

Answer:
NaZ + H2O <----> HZ + OH-
[OH-] = [HZ]
[NaZ] = 0.15 M
pH = 10.7, so the pOH = 14-10.7 = 3.3; [OH-] = 10^-3.3 = 5.01E-4
kb = [OH-][HZ]/[NaZ] = (5.01E-4)^2/0.15 = 1.67E-6
ka = kw/kb = 1E-14/1.67E-6 = 5.99E-9 = 6.0E-9