Question

What is the area of triangle ABC? Round to the nearest tenth of a square unit.

Answer 1

10*sin(72)*13*0.5, plug the number in calculator

Answer 2

`=61.8 units^2`.

Explanation:

In the picture we have that a = 13, b= 10 and C = 72°. Then,

`Area = (1)/(2)absin(C)`

`= (1)/(2)(13)(10)sin(72\°)`

`= 65sin(72\°)`

`=61.8 units^2`.