Question

If the equation of a circle is (x + 4)2 + (y - 6)2 = 25, its center point is

Answer 1

(-4, 6)

Step-by-step explanation:The center-radius form of a circle is the equation (x - h)^2 + (y - k)^2 = r^2 where (h,k) = center of circle r = radius of circle. Since the equation that was given is (x + 4)^2 + (y - 6)^2 = 25. then (x - h) = (x + 4) -h = 4 h = -4 (y - k) = (y - 6) - k = - 6 k = 6 So the center is (h,k) = (-4,6)

Answer 2

(-4, 6) The center-radius form of a circle is the equation (x - h)^2 + (y - k)^2 = r^2 where (h,k) = center of circle r = radius of circle. Since the equation that was given is (x + 4)^2 + (y - 6)^2 = 25. then (x - h) = (x + 4) -h = 4 h = -4 (y - k) = (y - 6) - k = - 6 k = 6 So the center is (h,k) = (-4,6)