Question

One integer is 8​ times another. if the product of the two integers is 288, then find the integers.

Answer 1

one integer is x
another integer is y

x=8y
xy=288

(8y)(y)=288
8y^2=288
Divide both sides by 8
y^2= 36
The square root of 36 is 6
y=6

x=8y = 8(6) = 48
x=48