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If there are x teams in a league and each team plays every other team​ twice, then the total number of games​ (n) to be played is given by nequals=xsquared2minus−x. a chess league has 1515 teams. what is the total number of games to be played if each team plays every other team​ twice?

asked
User Phonebox
by
7.8k points

2 Answers

6 votes

Final answer:

The total number of games to be played in a chess league with 15 teams is 210.

Step-by-step explanation:

The given formula to calculate the total number of games (n) to be played in a league with x teams is n = x^2 - x.

For the given chess league which has 15 teams, we can substitute x = 15 into the formula:

n = 15^2 - 15 = 225 - 15 = 210.

Therefore, the total number of games to be played in the chess league is 210.

answered
User Ferran Basora
by
8.2k points
1 vote
Given that if there are x teams in a league and each team plays every other team​ twice, then the total number of games​ (n) to be played is given by


n=x^2-x

If a chess league has 15 teams the total number of games to be played if each team plays every other team​ twice is given by


n=15^2-15 \\ \\ =225-15=210
answered
User Vulpo
by
8.6k points
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