Question

I neeed someone's HELP PLEASE!!!!!!!!!!!!!!!!!!!!11

Answer 1

you need to combine the numerator into one fraction and the denominator into one fraction so you can flip and multiply.


`Numerator\\ \\ (2)/(x) + 3( (x)/(x) ) = (2+3x)/(x) \\ \\ Denominator \\ \\ 1 ( (8x)/(8x)) - (1)/(8x) = (8x- 1)/(8x) \\ \\ flip-multiply \\ \\ (2+3x)/(x) ( (8x)/(8x-1) ) = (8(2+3x))/(8x-1) = (16+24x)/(8x-1)`

For the second question, factor everything.


`((q+8)(q-1))/((q-4)(q+1))`

Domain is the restriction on q. (remember denominator ≠ 0)
So q ≠ 4 or -1