asked 88.5k views
16 votes
A student in gym class swings from a rope and they are moving 5 m/s at the bottom of their swing. What is the height they reach above the floor before swinging back down?

1/2v^2=gh g = 9.8 m/s^2
A 2.55 m
B. 1.28 m
c. 5m
D. 12.5 m​

asked
User Akaliza
by
8.0k points

1 Answer

10 votes

Answer:

A

Step-by-step explanation:

answered
User DU Jiaen
by
8.2k points
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