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A dog eats 7 cans of food in 3 days. At this rate, how many cans of food does the dog eat in 3 + d days? the answer is 7 + 7d/3 but I don't know how to get to that.

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User AlmasB
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2 Answers

5 votes

Final answer:

To calculate how many cans of food a dog eats in 3 + d days, find the daily consumption rate by dividing 7 cans by 3 days to get 7/3 cans per day. Then multiply the rate by the total number of days (3 + d) to get the formula for total consumption, which results in 7 + 7d/3 cans.

Step-by-step explanation:

To determine how many cans of food a dog eats in 3 + d days, you first need to establish the rate at which the dog eats the food. Since the dog eats 7 cans of food in 3 days, the daily rate of consumption is 7 cans ÷ 3 days = 7/3 cans per day.

Next, to find out how many cans the dog will eat in 3 + d days, multiply the daily rate of consumption (7/3 cans per day) by the total number of days (3 + d days).

The calculation will look like this: (7/3 cans per day) × (3 + d days) = 7 + 7d/3 cans of food.

This gives you the equation for the total amount of food the dog will eat over the period of 3 + d days. So if d represents additional days, you can now determine the total by plugging any value of d into that formula.

answered
User NeverSleeps
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7.6k points
1 vote
7 cans --------------------- 3 days
x cans ---------------------- 3 + d days
-----------------------------------------------
We will make a proportion:
7 : x = 3 : ( 3 + d )
or:
7 / x = 3 / ( 3 + d ) / Then we will cross multiply.
7 * ( 3 + d ) = 3 x
21 + 7 d = 3 x
x = ( 21 + 7 d ) : 3
x = 7 + 7d/3 ( and this is your answer ).
answered
User Sekm
by
8.7k points

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