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Solve for x in the equation x^2-8x+41=0?

Solve for x in the equation x^2-8x+41=0?
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Solve for x in the equation x^2-8x+41=0?

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User Spooky
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1 Answer

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x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2

x = ( 8 + sqrt (-100) / 2 and (8 - sqrt(-100) / 2

4 +or- 5i

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User Simon Lenz
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8.0k points
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