asked 73.9k views
1 vote
Rectangle J’K’L’M shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applied on trapezoid STUV.

What will be the location of T’ in the image trapezoid S’T’U’V’?

A. (15, 2)

B. (18, 2)

C. (18, -2)

D. (15, -2)

Rectangle J’K’L’M shown on the grid is the image of rectangle JKLM after transformation-example-1
asked
User Amine
by
7.7k points

2 Answers

3 votes

The correct answer is:

B. (18, 2)

Step-by-step explanation:

The points of the pre-image JKLM are:

J(-7, -6); K(-4, -6); L(-4, -2); and M(-7, -2).

The points of image J'K'L'M' are:

J'(6, -9); K'(9, -9); L'(9, -5); and M'(6, -5).

Each point has moved horizontally 13 units and vertically -3 units; this gives us the translation <13, -3>.

Applying this to T, we have:

T'(5+13, 5-3) = (18, 2)

answered
User Gcharbon
by
7.9k points
3 votes

The answer is (18, 2) this is because the original figure JKLM used the rule (x+13, y-3) sorry not sure if I put that rule in the correct order.

answered
User Zajca
by
7.5k points
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