Question

Solve for x in the equation 2x^2-5x+1=3

Answer 1

`\text{The solution is } x=(5\pm √(41))/(4)`

Explanation:

Given quadratic equation

`2x^2-5x-2=0`

we have to solve the above equation for x.

`2x^2-5x-2=0\\\\\text{Comparing above equation with standard quadratic equation }\\ax^2+bx+c=0\text{, we get}\\\\a=2, b=-5, c=-2\\\\\text{The solution is }\\\\x=(-b\pm √(b^2-4ac))/(2a)\\\\x=(-(-5)\pm √(25-4(2)(-2)))/(2(2))\\\\x=(5\pm √(25+16))/(4)\\\\x=(5\pm √(41))/(4)\\\\\text{The solution is } x=(5\pm √(41))/(4)`

Answer 2

The answer would be x=5 over 4 ±√41/4