Question

What is the slope of a line perpendicular to the line whose equation is 2x+12y=-1922x+12y=−192. Fully reduce your answer.

Answer 1

The slope of the perpendicular line m =6

Explanation:

Step(i):-

Given that the equation of the straight line

2x + 12y =-192

⇒ 12 y = -192 -2x

`y = (-2x)/(12)- (192)/(12)`

`y = (-x)/(6) - 16`

y = m x +C

The slope of the given line
`m = (-1)/(6)`

Step(ii):-

The slope of the perpendicular line

`(-1)/(m)`

=
`(-1)/((-1)/(6) )`

The slope of the perpendicular line m =6