Question

A certain shade of blue has a frequency of 7.14 × 1014 hz. what is the energy of exactly one photon of this light?

Answer 1

For this problem, let's use the Planck's equation which is written below:

E = hv
where
E is the energy
h is Planck's constant equal to 6.626×10⁻³⁴ J·s
v is frequency

Solving for E,
E = (6.626×10⁻³⁴ J·s)(7.14×10¹⁴ s⁻¹)
E = 4.73×10⁻¹⁹ J