Question

Helppppppppppppppppppp

Answer 1

`\boxed{a_1=0.2}\\\\\\r=(-0.06)/(0.2)=\boxed{-0.3}`

so:


`a_n=a_1(r)^((n-1))\\\\\boxed{a_n=0.2(-0.3)^((n-1))}`

Answer E.