Question

If a gas in a closed container is pressurized from 15.2 atmospheres to 19.2 atmospheres and its original temperature was 25.0oC, what would the final temperature of the gas be?

Answer 1

From the gay lussac law which the pressure of a given amount of a gas held at constant volume is directly proportional to temperature in kelvin.
that is p1/T1=P2/T2
p1=15.2 atm
P2=19.2 atm
T1=25+273=298k
T2=?
15.2/298=19.2/T2
5721.6=15.2 T2 divide both sides by 15.2
therefore T2=376.4k or 103.4 degrees celsius