Question

What is the product? 4n/4n-4*n-1/n+1
A.)4n/n+1
B.)n/n+1
C.)1/n+1
D.)4/n+1

Answer 1

option (b) is correct.

The product of
`(4n)/(4n-4)` and
`(n-1)/(n+1)` is
`(n)/(n+1)`

Explanation:

Given
`(4n)/(4n-4)` and
`(n-1)/(n+1)`

We have to find the product of given two terms that is

`(4n)/(4n-4) * (n-1)/(n+1)`

Consider the product written as ,

`(4n)/(4n-4) * (n-1)/(n+1)`

Taking 4 common from the denominator of first term and simplify the first expression , we have,

`(4n)/(4(n-1)) * (n-1)/(n+1)`

`\Rightarrow (n)/((n-1)) * (n-1)/(n+1)`

(n-1 ) in numerator get canceled by (n-1 ) in denominator, we have,

`\Rightarrow (n)/(n+1)`

Thus, option (b) is correct.

The product of
`(4n)/(4n-4)` and
`(n-1)/(n+1)` is
`(n)/(n+1)`

Answer 2

B.) n/(n+1)

Explanation:

`(4n)/(4n-4)\cdot(n-1)/(n+1)=(4n(n-1))/(4(n-1)(n+1))\\\\=(n)/(n+1)\qquad\text{factors of 4 and n-1 cancel}`