Question

Write the point-slope form of the line that passes through (6, 1) and is perpendicular to a line with a slope of -3. Include all of your work in your final answer. Type your answer in the box provided or use the upload option to submit your solution.

Answer 1

y - 1 = 1/3 (x - 6) would be your answer.
Hope this helps!!

Answer 2

The point slope form of required line is
`y-1=(1)/(3)(x-6)`.

Explanation:

It is given the the required line passes through the point (6,1) and perpendicular to a line with a slope of -3.

The product of slopes of two perpendicular lines is -1.

Let the slope of required line be m.

`m* -3=-1`

Divide both sides by -3.

`m=(-1)/(-3)`

`m=(1)/(3)`

The slope of required line is 1/3.

If a line passes through the point
`(x_1,y_1)` with sloe m, then the point slope form of the line is

`y-y_1=m(x-x_1)`

The point slope form of required line is

`y-1=(1)/(3)(x-6)`

Therefore the point slope form of required line is
`y-1=(1)/(3)(x-6)`.