Question

A train is moving 4.82 m/s when it begins to accelerate. After 24.8s it is moving 7.09m/s how far did it move in that time

Answer 1

The train's average speed during that 24.8 seconds is

(1/2) (4.82 m/s + 7.09 m/s)

= (1/2) (11.91 m/s)

= 5.955 m/s .

Traveling at an average speed of 5.955 m/s for 24.8 sec,
it covers

(5.955 m/s) x (24.8 sec) = 147.68 meters .