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Given h(t)=-2(t+5)^2+4, find h(-8)

Given h(t)=-2(t+5)^2+4, find h(-8)
asked 71.3k views
4 votes
Given h(t)=-2(t+5)^2+4, find h(-8)

asked
User Humberd
by
8.2k points

2 Answers

6 votes

Answer:

-14

Explanation:

h(-8) = -18 + 4 = -14

answered
User Paul Panzer
by
8.7k points
2 votes
Substitute -8 for t in h(t)=-2(t+5)^2+4:

h(-8) = -2(-8+5)^2 + 4 = -2(-3)^2 + 4 = -2(9) + 4 = -18 + 4

h(-8) = -18 + 4 = -14 (answer)
answered
User Tim Andrews
by
8.0k points
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