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What is the equation of a line perpendicular to the line 7x+4y=15+2x and passes through the point (0.5,0.5)?

What is the equation of a line perpendicular to the line 7x+4y=15+2x and passes through the point (0.5,0.5)?
asked 150k views
2 votes
What is the equation of a line perpendicular to the line 7x+4y=15+2x and passes through the point (0.5,0.5)?

asked
User Morgan
by
8.4k points

1 Answer

4 votes
4y=-5x+15
y=-5/4x+15/4
y-1/2=4/5(x-1/2)
y-1/2=4/5x-2/5
y-5/10=4/5x-4/10
y=4/5x+1/10
answered
User Yugo Amaryl
by
7.5k points
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