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The probability that a monohybrid cross of two heterozygotes will produce an individual exhibiting the recessive trait is: A:3/4 B:1/4 C:100% C:1/16

The probability that a monohybrid cross of two heterozygotes will produce an individual exhibiting the recessive trait is: A:3/4 B:1/4 C:100% C:1/16
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The probability that a monohybrid cross of two heterozygotes will produce an individual exhibiting the recessive trait is: A:3/4 B:1/4 C:100% C:1/16

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User Hyztname
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The answer is B, 1/4

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User Jackiszhp
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