Question

PLZZZZ HELPPPPP
QUESTION 14 R

Answer 1

`|\overrightarrow{WX}|=√((6-6)^2+(3-(-3))^2+(4-6)^2)=√(0^2+6^2+(-2)^2)=\\\\=√(0+36+4)=√(40)=√(4\cdot10)=√(4)\cdot√(10)=\boxed{2√(10)}`

Answer a)