Question

What are the zeros of f(x) = x2 – 8x + 16?

Answer 1

It would be
Answer: the zeroes are at
x = 4
Step-by-step explanation:
Factor it out:
ask yourself: what factors multiply to
16 and add up to − 8

thus
f(x) = (-4)(x - 4) x - 4 = 0

X = 4

Answer 2

x^2 – 8x + 16 = 0
(x - 4)^2 = 0
x - 4 = 0
x = 4

hope it helps